\(\int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx\) [40]

Optimal result

Integrand size = 20, antiderivative size = 65 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=-\frac {c^5 (a-b x)^6}{8 x^8}-\frac {5 b c^5 (a-b x)^6}{28 a x^7}-\frac {5 b^2 c^5 (a-b x)^6}{168 a^2 x^6} \]

[Out]

-1/8*c^5*(-b*x+a)^6/x^8-5/28*b*c^5*(-b*x+a)^6/a/x^7-5/168*b^2*c^5*(-b*x+a)^6/a^2/x^6

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {79, 47, 37} \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=-\frac {5 b^2 c^5 (a-b x)^6}{168 a^2 x^6}-\frac {c^5 (a-b x)^6}{8 x^8}-\frac {5 b c^5 (a-b x)^6}{28 a x^7} \]

[In]

Int[((a + b*x)*(a*c - b*c*x)^5)/x^9,x]

[Out]

-1/8*(c^5*(a - b*x)^6)/x^8 - (5*b*c^5*(a - b*x)^6)/(28*a*x^7) - (5*b^2*c^5*(a - b*x)^6)/(168*a^2*x^6)

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*(Simplify[m + n + 2]/((b*c - a*d)*(m + 1))), Int[(a + b*x)^Simplify[m +
1]*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[Simplify[m + n + 2], 0] &&
NeQ[m, -1] &&  !(LtQ[m, -1] && LtQ[n, -1] && (EqQ[a, 0] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && (
SumSimplerQ[m, 1] ||  !SumSimplerQ[n, 1])

Rule 79

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(-(b*e - a*f
))*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(f*(p + 1)*(c*f - d*e))), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1
) + c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e,
f, n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || L
tQ[p, n]))))

Rubi steps \begin{align*} \text {integral}& = -\frac {c^5 (a-b x)^6}{8 x^8}+\frac {1}{4} (5 b) \int \frac {(a c-b c x)^5}{x^8} \, dx \\ & = -\frac {c^5 (a-b x)^6}{8 x^8}-\frac {5 b c^5 (a-b x)^6}{28 a x^7}+\frac {\left (5 b^2\right ) \int \frac {(a c-b c x)^5}{x^7} \, dx}{28 a} \\ & = -\frac {c^5 (a-b x)^6}{8 x^8}-\frac {5 b c^5 (a-b x)^6}{28 a x^7}-\frac {5 b^2 c^5 (a-b x)^6}{168 a^2 x^6} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.12 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=c^5 \left (-\frac {a^6}{8 x^8}+\frac {4 a^5 b}{7 x^7}-\frac {5 a^4 b^2}{6 x^6}+\frac {5 a^2 b^4}{4 x^4}-\frac {4 a b^5}{3 x^3}+\frac {b^6}{2 x^2}\right ) \]

[In]

Integrate[((a + b*x)*(a*c - b*c*x)^5)/x^9,x]

[Out]

c^5*(-1/8*a^6/x^8 + (4*a^5*b)/(7*x^7) - (5*a^4*b^2)/(6*x^6) + (5*a^2*b^4)/(4*x^4) - (4*a*b^5)/(3*x^3) + b^6/(2
*x^2))

Maple [A] (verified)

Time = 0.86 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.94

method	result	size
gosper	\(-\frac {c^{5} \left (-84 b^{6} x^{6}+224 a \,x^{5} b^{5}-210 a^{2} x^{4} b^{4}+140 a^{4} x^{2} b^{2}-96 a^{5} x b +21 a^{6}\right )}{168 x^{8}}\)	\(61\)
default	\(c^{5} \left (-\frac {5 a^{4} b^{2}}{6 x^{6}}+\frac {4 a^{5} b}{7 x^{7}}-\frac {a^{6}}{8 x^{8}}-\frac {4 a \,b^{5}}{3 x^{3}}+\frac {b^{6}}{2 x^{2}}+\frac {5 a^{2} b^{4}}{4 x^{4}}\right )\)	\(62\)
norman	\(\frac {-\frac {1}{8} a^{6} c^{5}+\frac {1}{2} b^{6} c^{5} x^{6}-\frac {4}{3} a \,b^{5} c^{5} x^{5}+\frac {5}{4} a^{2} b^{4} c^{5} x^{4}-\frac {5}{6} a^{4} b^{2} c^{5} x^{2}+\frac {4}{7} a^{5} b \,c^{5} x}{x^{8}}\)	\(75\)
risch	\(\frac {-\frac {1}{8} a^{6} c^{5}+\frac {1}{2} b^{6} c^{5} x^{6}-\frac {4}{3} a \,b^{5} c^{5} x^{5}+\frac {5}{4} a^{2} b^{4} c^{5} x^{4}-\frac {5}{6} a^{4} b^{2} c^{5} x^{2}+\frac {4}{7} a^{5} b \,c^{5} x}{x^{8}}\)	\(75\)
parallelrisch	\(\frac {84 b^{6} c^{5} x^{6}-224 a \,b^{5} c^{5} x^{5}+210 a^{2} b^{4} c^{5} x^{4}-140 a^{4} b^{2} c^{5} x^{2}+96 a^{5} b \,c^{5} x -21 a^{6} c^{5}}{168 x^{8}}\)	\(76\)

[In]

int((b*x+a)*(-b*c*x+a*c)^5/x^9,x,method=_RETURNVERBOSE)

[Out]

-1/168*c^5*(-84*b^6*x^6+224*a*b^5*x^5-210*a^2*b^4*x^4+140*a^4*b^2*x^2-96*a^5*b*x+21*a^6)/x^8

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.15 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=\frac {84 \, b^{6} c^{5} x^{6} - 224 \, a b^{5} c^{5} x^{5} + 210 \, a^{2} b^{4} c^{5} x^{4} - 140 \, a^{4} b^{2} c^{5} x^{2} + 96 \, a^{5} b c^{5} x - 21 \, a^{6} c^{5}}{168 \, x^{8}} \]

[In]

integrate((b*x+a)*(-b*c*x+a*c)^5/x^9,x, algorithm="fricas")

[Out]

1/168*(84*b^6*c^5*x^6 - 224*a*b^5*c^5*x^5 + 210*a^2*b^4*c^5*x^4 - 140*a^4*b^2*c^5*x^2 + 96*a^5*b*c^5*x - 21*a^
6*c^5)/x^8

Sympy [A] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.26 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=- \frac {21 a^{6} c^{5} - 96 a^{5} b c^{5} x + 140 a^{4} b^{2} c^{5} x^{2} - 210 a^{2} b^{4} c^{5} x^{4} + 224 a b^{5} c^{5} x^{5} - 84 b^{6} c^{5} x^{6}}{168 x^{8}} \]

[In]

integrate((b*x+a)*(-b*c*x+a*c)**5/x**9,x)

[Out]

-(21*a**6*c**5 - 96*a**5*b*c**5*x + 140*a**4*b**2*c**5*x**2 - 210*a**2*b**4*c**5*x**4 + 224*a*b**5*c**5*x**5 -
84*b**6*c**5*x**6)/(168*x**8)

Maxima [A] (verification not implemented)

none

Time = 0.20 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.15 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=\frac {84 \, b^{6} c^{5} x^{6} - 224 \, a b^{5} c^{5} x^{5} + 210 \, a^{2} b^{4} c^{5} x^{4} - 140 \, a^{4} b^{2} c^{5} x^{2} + 96 \, a^{5} b c^{5} x - 21 \, a^{6} c^{5}}{168 \, x^{8}} \]

[In]

integrate((b*x+a)*(-b*c*x+a*c)^5/x^9,x, algorithm="maxima")

[Out]

1/168*(84*b^6*c^5*x^6 - 224*a*b^5*c^5*x^5 + 210*a^2*b^4*c^5*x^4 - 140*a^4*b^2*c^5*x^2 + 96*a^5*b*c^5*x - 21*a^
6*c^5)/x^8

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.15 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=\frac {84 \, b^{6} c^{5} x^{6} - 224 \, a b^{5} c^{5} x^{5} + 210 \, a^{2} b^{4} c^{5} x^{4} - 140 \, a^{4} b^{2} c^{5} x^{2} + 96 \, a^{5} b c^{5} x - 21 \, a^{6} c^{5}}{168 \, x^{8}} \]

[In]

integrate((b*x+a)*(-b*c*x+a*c)^5/x^9,x, algorithm="giac")

[Out]

1/168*(84*b^6*c^5*x^6 - 224*a*b^5*c^5*x^5 + 210*a^2*b^4*c^5*x^4 - 140*a^4*b^2*c^5*x^2 + 96*a^5*b*c^5*x - 21*a^
6*c^5)/x^8

Mupad [B] (verification not implemented)

Time = 0.06 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.15 \[ \int \frac {(a+b x) (a c-b c x)^5}{x^9} \, dx=-\frac {\frac {a^6\,c^5}{8}-\frac {4\,a^5\,b\,c^5\,x}{7}+\frac {5\,a^4\,b^2\,c^5\,x^2}{6}-\frac {5\,a^2\,b^4\,c^5\,x^4}{4}+\frac {4\,a\,b^5\,c^5\,x^5}{3}-\frac {b^6\,c^5\,x^6}{2}}{x^8} \]

[In]

int(((a*c - b*c*x)^5*(a + b*x))/x^9,x)

[Out]

-((a^6*c^5)/8 - (b^6*c^5*x^6)/2 + (4*a*b^5*c^5*x^5)/3 + (5*a^4*b^2*c^5*x^2)/6 - (5*a^2*b^4*c^5*x^4)/4 - (4*a^5
*b*c^5*x)/7)/x^8